fill in the blank because i am confused and need help for 10 points?

Question: given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. Give the shape as trianglem quadrilateral or unbounded report your vertices starting with the one which has the smallest x-value. if more than one vertex has the same, smallese x-value, start with the one that has the smallest y value. Proceed clockwise from the first vertex x+y< or equal to 4 4x +y < or equal to 5 x> or equal to 0 y> or equal to 0 the shape of the feasible region is quadrilateral the first vertex is (_____,____) the second vertex is (_____,______) the third vertex is (_______,________) the fourth vertex is (______, 0)

Answer: hi 1) x + y = 4 2) 4 x + y = 5 then 2) - 1) 3 x = 1 x = 1/3 -> y = 11/3 Va( 1/3 , 11/3) x + y = 4; y = 0 x0a = 4 4 x + y = 5 ; y = 0 x0b = 5/4 then x0b < x0a Vb ( 5/4 ; 0) x + y = 4; x = 0 y0a = 4 4 x + y = 5 ; x = 0 y0b = 5 then y0a < y0b Vc ( 0; 4 ) x=0 ; y = 0 Vd ( 0,0) smallest Vd 1* vertex (0,0) 2* vertex (0.4) 3* vertex (1/3 ; 11/3) 4* vertex ( 5/4 ; 0 ) greetings

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